3.10.81 \(\int \frac {A+B x}{(a+b x) (d+e x)^4} \, dx\)

Optimal. Leaf size=146 \[ \frac {b^2 (A b-a B) \log (a+b x)}{(b d-a e)^4}-\frac {b^2 (A b-a B) \log (d+e x)}{(b d-a e)^4}+\frac {b (A b-a B)}{(d+e x) (b d-a e)^3}+\frac {A b-a B}{2 (d+e x)^2 (b d-a e)^2}+\frac {A e-B d}{3 e (d+e x)^3 (b d-a e)} \]

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Rubi [A]  time = 0.12, antiderivative size = 146, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {77} \begin {gather*} \frac {b^2 (A b-a B) \log (a+b x)}{(b d-a e)^4}-\frac {b^2 (A b-a B) \log (d+e x)}{(b d-a e)^4}+\frac {b (A b-a B)}{(d+e x) (b d-a e)^3}+\frac {A b-a B}{2 (d+e x)^2 (b d-a e)^2}-\frac {B d-A e}{3 e (d+e x)^3 (b d-a e)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(A + B*x)/((a + b*x)*(d + e*x)^4),x]

[Out]

-(B*d - A*e)/(3*e*(b*d - a*e)*(d + e*x)^3) + (A*b - a*B)/(2*(b*d - a*e)^2*(d + e*x)^2) + (b*(A*b - a*B))/((b*d
- a*e)^3*(d + e*x)) + (b^2*(A*b - a*B)*Log[a + b*x])/(b*d - a*e)^4 - (b^2*(A*b - a*B)*Log[d + e*x])/(b*d - a*
e)^4

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int \frac {A+B x}{(a+b x) (d+e x)^4} \, dx &=\int \left (\frac {b^3 (A b-a B)}{(b d-a e)^4 (a+b x)}+\frac {B d-A e}{(b d-a e) (d+e x)^4}+\frac {(-A b+a B) e}{(b d-a e)^2 (d+e x)^3}+\frac {b (A b-a B) e}{(-b d+a e)^3 (d+e x)^2}-\frac {b^2 (A b-a B) e}{(-b d+a e)^4 (d+e x)}\right ) \, dx\\ &=-\frac {B d-A e}{3 e (b d-a e) (d+e x)^3}+\frac {A b-a B}{2 (b d-a e)^2 (d+e x)^2}+\frac {b (A b-a B)}{(b d-a e)^3 (d+e x)}+\frac {b^2 (A b-a B) \log (a+b x)}{(b d-a e)^4}-\frac {b^2 (A b-a B) \log (d+e x)}{(b d-a e)^4}\\ \end {align*}

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Mathematica [A]  time = 0.25, size = 145, normalized size = 0.99 \begin {gather*} \frac {b^2 (A b-a B) \log (a+b x)}{(b d-a e)^4}+\frac {b^2 (a B-A b) \log (d+e x)}{(b d-a e)^4}+\frac {b (A b-a B)}{(d+e x) (b d-a e)^3}+\frac {A b-a B}{2 (d+e x)^2 (b d-a e)^2}+\frac {B d-A e}{3 e (d+e x)^3 (a e-b d)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x)/((a + b*x)*(d + e*x)^4),x]

[Out]

(B*d - A*e)/(3*e*(-(b*d) + a*e)*(d + e*x)^3) + (A*b - a*B)/(2*(b*d - a*e)^2*(d + e*x)^2) + (b*(A*b - a*B))/((b
*d - a*e)^3*(d + e*x)) + (b^2*(A*b - a*B)*Log[a + b*x])/(b*d - a*e)^4 + (b^2*(-(A*b) + a*B)*Log[d + e*x])/(b*d
- a*e)^4

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {A+B x}{(a+b x) (d+e x)^4} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(A + B*x)/((a + b*x)*(d + e*x)^4),x]

[Out]

IntegrateAlgebraic[(A + B*x)/((a + b*x)*(d + e*x)^4), x]

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fricas [B]  time = 1.29, size = 608, normalized size = 4.16 \begin {gather*} -\frac {2 \, B b^{3} d^{4} + 2 \, A a^{3} e^{4} + {\left (3 \, B a b^{2} - 11 \, A b^{3}\right )} d^{3} e - 6 \, {\left (B a^{2} b - 3 \, A a b^{2}\right )} d^{2} e^{2} + {\left (B a^{3} - 9 \, A a^{2} b\right )} d e^{3} + 6 \, {\left ({\left (B a b^{2} - A b^{3}\right )} d e^{3} - {\left (B a^{2} b - A a b^{2}\right )} e^{4}\right )} x^{2} + 3 \, {\left (5 \, {\left (B a b^{2} - A b^{3}\right )} d^{2} e^{2} - 6 \, {\left (B a^{2} b - A a b^{2}\right )} d e^{3} + {\left (B a^{3} - A a^{2} b\right )} e^{4}\right )} x + 6 \, {\left ({\left (B a b^{2} - A b^{3}\right )} e^{4} x^{3} + 3 \, {\left (B a b^{2} - A b^{3}\right )} d e^{3} x^{2} + 3 \, {\left (B a b^{2} - A b^{3}\right )} d^{2} e^{2} x + {\left (B a b^{2} - A b^{3}\right )} d^{3} e\right )} \log \left (b x + a\right ) - 6 \, {\left ({\left (B a b^{2} - A b^{3}\right )} e^{4} x^{3} + 3 \, {\left (B a b^{2} - A b^{3}\right )} d e^{3} x^{2} + 3 \, {\left (B a b^{2} - A b^{3}\right )} d^{2} e^{2} x + {\left (B a b^{2} - A b^{3}\right )} d^{3} e\right )} \log \left (e x + d\right )}{6 \, {\left (b^{4} d^{7} e - 4 \, a b^{3} d^{6} e^{2} + 6 \, a^{2} b^{2} d^{5} e^{3} - 4 \, a^{3} b d^{4} e^{4} + a^{4} d^{3} e^{5} + {\left (b^{4} d^{4} e^{4} - 4 \, a b^{3} d^{3} e^{5} + 6 \, a^{2} b^{2} d^{2} e^{6} - 4 \, a^{3} b d e^{7} + a^{4} e^{8}\right )} x^{3} + 3 \, {\left (b^{4} d^{5} e^{3} - 4 \, a b^{3} d^{4} e^{4} + 6 \, a^{2} b^{2} d^{3} e^{5} - 4 \, a^{3} b d^{2} e^{6} + a^{4} d e^{7}\right )} x^{2} + 3 \, {\left (b^{4} d^{6} e^{2} - 4 \, a b^{3} d^{5} e^{3} + 6 \, a^{2} b^{2} d^{4} e^{4} - 4 \, a^{3} b d^{3} e^{5} + a^{4} d^{2} e^{6}\right )} x\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b*x+a)/(e*x+d)^4,x, algorithm="fricas")

[Out]

-1/6*(2*B*b^3*d^4 + 2*A*a^3*e^4 + (3*B*a*b^2 - 11*A*b^3)*d^3*e - 6*(B*a^2*b - 3*A*a*b^2)*d^2*e^2 + (B*a^3 - 9*
A*a^2*b)*d*e^3 + 6*((B*a*b^2 - A*b^3)*d*e^3 - (B*a^2*b - A*a*b^2)*e^4)*x^2 + 3*(5*(B*a*b^2 - A*b^3)*d^2*e^2 -
6*(B*a^2*b - A*a*b^2)*d*e^3 + (B*a^3 - A*a^2*b)*e^4)*x + 6*((B*a*b^2 - A*b^3)*e^4*x^3 + 3*(B*a*b^2 - A*b^3)*d*
e^3*x^2 + 3*(B*a*b^2 - A*b^3)*d^2*e^2*x + (B*a*b^2 - A*b^3)*d^3*e)*log(b*x + a) - 6*((B*a*b^2 - A*b^3)*e^4*x^3
+ 3*(B*a*b^2 - A*b^3)*d*e^3*x^2 + 3*(B*a*b^2 - A*b^3)*d^2*e^2*x + (B*a*b^2 - A*b^3)*d^3*e)*log(e*x + d))/(b^4
*d^7*e - 4*a*b^3*d^6*e^2 + 6*a^2*b^2*d^5*e^3 - 4*a^3*b*d^4*e^4 + a^4*d^3*e^5 + (b^4*d^4*e^4 - 4*a*b^3*d^3*e^5
+ 6*a^2*b^2*d^2*e^6 - 4*a^3*b*d*e^7 + a^4*e^8)*x^3 + 3*(b^4*d^5*e^3 - 4*a*b^3*d^4*e^4 + 6*a^2*b^2*d^3*e^5 - 4*
a^3*b*d^2*e^6 + a^4*d*e^7)*x^2 + 3*(b^4*d^6*e^2 - 4*a*b^3*d^5*e^3 + 6*a^2*b^2*d^4*e^4 - 4*a^3*b*d^3*e^5 + a^4*
d^2*e^6)*x)

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giac [B]  time = 1.46, size = 362, normalized size = 2.48 \begin {gather*} -\frac {{\left (B a b^{3} - A b^{4}\right )} \log \left ({\left | b x + a \right |}\right )}{b^{5} d^{4} - 4 \, a b^{4} d^{3} e + 6 \, a^{2} b^{3} d^{2} e^{2} - 4 \, a^{3} b^{2} d e^{3} + a^{4} b e^{4}} + \frac {{\left (B a b^{2} e - A b^{3} e\right )} \log \left ({\left | x e + d \right |}\right )}{b^{4} d^{4} e - 4 \, a b^{3} d^{3} e^{2} + 6 \, a^{2} b^{2} d^{2} e^{3} - 4 \, a^{3} b d e^{4} + a^{4} e^{5}} - \frac {{\left (2 \, B b^{3} d^{4} + 3 \, B a b^{2} d^{3} e - 11 \, A b^{3} d^{3} e - 6 \, B a^{2} b d^{2} e^{2} + 18 \, A a b^{2} d^{2} e^{2} + B a^{3} d e^{3} - 9 \, A a^{2} b d e^{3} + 2 \, A a^{3} e^{4} + 6 \, {\left (B a b^{2} d e^{3} - A b^{3} d e^{3} - B a^{2} b e^{4} + A a b^{2} e^{4}\right )} x^{2} + 3 \, {\left (5 \, B a b^{2} d^{2} e^{2} - 5 \, A b^{3} d^{2} e^{2} - 6 \, B a^{2} b d e^{3} + 6 \, A a b^{2} d e^{3} + B a^{3} e^{4} - A a^{2} b e^{4}\right )} x\right )} e^{\left (-1\right )}}{6 \, {\left (b d - a e\right )}^{4} {\left (x e + d\right )}^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b*x+a)/(e*x+d)^4,x, algorithm="giac")

[Out]

-(B*a*b^3 - A*b^4)*log(abs(b*x + a))/(b^5*d^4 - 4*a*b^4*d^3*e + 6*a^2*b^3*d^2*e^2 - 4*a^3*b^2*d*e^3 + a^4*b*e^
4) + (B*a*b^2*e - A*b^3*e)*log(abs(x*e + d))/(b^4*d^4*e - 4*a*b^3*d^3*e^2 + 6*a^2*b^2*d^2*e^3 - 4*a^3*b*d*e^4
+ a^4*e^5) - 1/6*(2*B*b^3*d^4 + 3*B*a*b^2*d^3*e - 11*A*b^3*d^3*e - 6*B*a^2*b*d^2*e^2 + 18*A*a*b^2*d^2*e^2 + B*
a^3*d*e^3 - 9*A*a^2*b*d*e^3 + 2*A*a^3*e^4 + 6*(B*a*b^2*d*e^3 - A*b^3*d*e^3 - B*a^2*b*e^4 + A*a*b^2*e^4)*x^2 +
3*(5*B*a*b^2*d^2*e^2 - 5*A*b^3*d^2*e^2 - 6*B*a^2*b*d*e^3 + 6*A*a*b^2*d*e^3 + B*a^3*e^4 - A*a^2*b*e^4)*x)*e^(-1
)/((b*d - a*e)^4*(x*e + d)^3)

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maple [A]  time = 0.01, size = 220, normalized size = 1.51 \begin {gather*} \frac {A \,b^{3} \ln \left (b x +a \right )}{\left (a e -b d \right )^{4}}-\frac {A \,b^{3} \ln \left (e x +d \right )}{\left (a e -b d \right )^{4}}-\frac {B a \,b^{2} \ln \left (b x +a \right )}{\left (a e -b d \right )^{4}}+\frac {B a \,b^{2} \ln \left (e x +d \right )}{\left (a e -b d \right )^{4}}-\frac {A \,b^{2}}{\left (a e -b d \right )^{3} \left (e x +d \right )}+\frac {B a b}{\left (a e -b d \right )^{3} \left (e x +d \right )}+\frac {A b}{2 \left (a e -b d \right )^{2} \left (e x +d \right )^{2}}-\frac {B a}{2 \left (a e -b d \right )^{2} \left (e x +d \right )^{2}}-\frac {A}{3 \left (a e -b d \right ) \left (e x +d \right )^{3}}+\frac {B d}{3 \left (a e -b d \right ) \left (e x +d \right )^{3} e} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x+A)/(b*x+a)/(e*x+d)^4,x)

[Out]

-1/3/(a*e-b*d)/(e*x+d)^3*A+1/3/(a*e-b*d)/e/(e*x+d)^3*B*d-b^2/(a*e-b*d)^3/(e*x+d)*A+b/(a*e-b*d)^3/(e*x+d)*B*a+1
/2/(a*e-b*d)^2/(e*x+d)^2*A*b-1/2/(a*e-b*d)^2/(e*x+d)^2*B*a-b^3/(a*e-b*d)^4*ln(e*x+d)*A+b^2/(a*e-b*d)^4*ln(e*x+
d)*B*a+b^3/(a*e-b*d)^4*ln(b*x+a)*A-b^2/(a*e-b*d)^4*ln(b*x+a)*B*a

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maxima [B]  time = 0.68, size = 444, normalized size = 3.04 \begin {gather*} -\frac {{\left (B a b^{2} - A b^{3}\right )} \log \left (b x + a\right )}{b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}} + \frac {{\left (B a b^{2} - A b^{3}\right )} \log \left (e x + d\right )}{b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}} - \frac {2 \, B b^{2} d^{3} - 2 \, A a^{2} e^{3} + 6 \, {\left (B a b - A b^{2}\right )} e^{3} x^{2} + {\left (5 \, B a b - 11 \, A b^{2}\right )} d^{2} e - {\left (B a^{2} - 7 \, A a b\right )} d e^{2} + 3 \, {\left (5 \, {\left (B a b - A b^{2}\right )} d e^{2} - {\left (B a^{2} - A a b\right )} e^{3}\right )} x}{6 \, {\left (b^{3} d^{6} e - 3 \, a b^{2} d^{5} e^{2} + 3 \, a^{2} b d^{4} e^{3} - a^{3} d^{3} e^{4} + {\left (b^{3} d^{3} e^{4} - 3 \, a b^{2} d^{2} e^{5} + 3 \, a^{2} b d e^{6} - a^{3} e^{7}\right )} x^{3} + 3 \, {\left (b^{3} d^{4} e^{3} - 3 \, a b^{2} d^{3} e^{4} + 3 \, a^{2} b d^{2} e^{5} - a^{3} d e^{6}\right )} x^{2} + 3 \, {\left (b^{3} d^{5} e^{2} - 3 \, a b^{2} d^{4} e^{3} + 3 \, a^{2} b d^{3} e^{4} - a^{3} d^{2} e^{5}\right )} x\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b*x+a)/(e*x+d)^4,x, algorithm="maxima")

[Out]

-(B*a*b^2 - A*b^3)*log(b*x + a)/(b^4*d^4 - 4*a*b^3*d^3*e + 6*a^2*b^2*d^2*e^2 - 4*a^3*b*d*e^3 + a^4*e^4) + (B*a
*b^2 - A*b^3)*log(e*x + d)/(b^4*d^4 - 4*a*b^3*d^3*e + 6*a^2*b^2*d^2*e^2 - 4*a^3*b*d*e^3 + a^4*e^4) - 1/6*(2*B*
b^2*d^3 - 2*A*a^2*e^3 + 6*(B*a*b - A*b^2)*e^3*x^2 + (5*B*a*b - 11*A*b^2)*d^2*e - (B*a^2 - 7*A*a*b)*d*e^2 + 3*(
5*(B*a*b - A*b^2)*d*e^2 - (B*a^2 - A*a*b)*e^3)*x)/(b^3*d^6*e - 3*a*b^2*d^5*e^2 + 3*a^2*b*d^4*e^3 - a^3*d^3*e^4
+ (b^3*d^3*e^4 - 3*a*b^2*d^2*e^5 + 3*a^2*b*d*e^6 - a^3*e^7)*x^3 + 3*(b^3*d^4*e^3 - 3*a*b^2*d^3*e^4 + 3*a^2*b*
d^2*e^5 - a^3*d*e^6)*x^2 + 3*(b^3*d^5*e^2 - 3*a*b^2*d^4*e^3 + 3*a^2*b*d^3*e^4 - a^3*d^2*e^5)*x)

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mupad [B]  time = 1.37, size = 399, normalized size = 2.73 \begin {gather*} \frac {2\,b^2\,\mathrm {atanh}\left (\frac {\left (\frac {a^4\,e^4-2\,a^3\,b\,d\,e^3+2\,a\,b^3\,d^3\,e-b^4\,d^4}{a^3\,e^3-3\,a^2\,b\,d\,e^2+3\,a\,b^2\,d^2\,e-b^3\,d^3}+2\,b\,e\,x\right )\,\left (a^3\,e^3-3\,a^2\,b\,d\,e^2+3\,a\,b^2\,d^2\,e-b^3\,d^3\right )}{{\left (a\,e-b\,d\right )}^4}\right )\,\left (A\,b-B\,a\right )}{{\left (a\,e-b\,d\right )}^4}-\frac {\frac {B\,a^2\,d\,e^2+2\,A\,a^2\,e^3-5\,B\,a\,b\,d^2\,e-7\,A\,a\,b\,d\,e^2-2\,B\,b^2\,d^3+11\,A\,b^2\,d^2\,e}{6\,e\,\left (a^3\,e^3-3\,a^2\,b\,d\,e^2+3\,a\,b^2\,d^2\,e-b^3\,d^3\right )}-\frac {x\,\left (A\,b-B\,a\right )\,\left (a\,e^2-5\,b\,d\,e\right )}{2\,\left (a^3\,e^3-3\,a^2\,b\,d\,e^2+3\,a\,b^2\,d^2\,e-b^3\,d^3\right )}+\frac {b\,e^2\,x^2\,\left (A\,b-B\,a\right )}{a^3\,e^3-3\,a^2\,b\,d\,e^2+3\,a\,b^2\,d^2\,e-b^3\,d^3}}{d^3+3\,d^2\,e\,x+3\,d\,e^2\,x^2+e^3\,x^3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*x)/((a + b*x)*(d + e*x)^4),x)

[Out]

(2*b^2*atanh((((a^4*e^4 - b^4*d^4 + 2*a*b^3*d^3*e - 2*a^3*b*d*e^3)/(a^3*e^3 - b^3*d^3 + 3*a*b^2*d^2*e - 3*a^2*
b*d*e^2) + 2*b*e*x)*(a^3*e^3 - b^3*d^3 + 3*a*b^2*d^2*e - 3*a^2*b*d*e^2))/(a*e - b*d)^4)*(A*b - B*a))/(a*e - b*
d)^4 - ((2*A*a^2*e^3 - 2*B*b^2*d^3 + 11*A*b^2*d^2*e + B*a^2*d*e^2 - 7*A*a*b*d*e^2 - 5*B*a*b*d^2*e)/(6*e*(a^3*e
^3 - b^3*d^3 + 3*a*b^2*d^2*e - 3*a^2*b*d*e^2)) - (x*(A*b - B*a)*(a*e^2 - 5*b*d*e))/(2*(a^3*e^3 - b^3*d^3 + 3*a
*b^2*d^2*e - 3*a^2*b*d*e^2)) + (b*e^2*x^2*(A*b - B*a))/(a^3*e^3 - b^3*d^3 + 3*a*b^2*d^2*e - 3*a^2*b*d*e^2))/(d
^3 + e^3*x^3 + 3*d*e^2*x^2 + 3*d^2*e*x)

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sympy [B]  time = 3.03, size = 818, normalized size = 5.60 \begin {gather*} \frac {b^{2} \left (- A b + B a\right ) \log {\left (x + \frac {- A a b^{3} e - A b^{4} d + B a^{2} b^{2} e + B a b^{3} d - \frac {a^{5} b^{2} e^{5} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} + \frac {5 a^{4} b^{3} d e^{4} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} - \frac {10 a^{3} b^{4} d^{2} e^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} + \frac {10 a^{2} b^{5} d^{3} e^{2} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} - \frac {5 a b^{6} d^{4} e \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} + \frac {b^{7} d^{5} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}}}{- 2 A b^{4} e + 2 B a b^{3} e} \right )}}{\left (a e - b d\right )^{4}} - \frac {b^{2} \left (- A b + B a\right ) \log {\left (x + \frac {- A a b^{3} e - A b^{4} d + B a^{2} b^{2} e + B a b^{3} d + \frac {a^{5} b^{2} e^{5} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} - \frac {5 a^{4} b^{3} d e^{4} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} + \frac {10 a^{3} b^{4} d^{2} e^{3} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} - \frac {10 a^{2} b^{5} d^{3} e^{2} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} + \frac {5 a b^{6} d^{4} e \left (- A b + B a\right )}{\left (a e - b d\right )^{4}} - \frac {b^{7} d^{5} \left (- A b + B a\right )}{\left (a e - b d\right )^{4}}}{- 2 A b^{4} e + 2 B a b^{3} e} \right )}}{\left (a e - b d\right )^{4}} + \frac {- 2 A a^{2} e^{3} + 7 A a b d e^{2} - 11 A b^{2} d^{2} e - B a^{2} d e^{2} + 5 B a b d^{2} e + 2 B b^{2} d^{3} + x^{2} \left (- 6 A b^{2} e^{3} + 6 B a b e^{3}\right ) + x \left (3 A a b e^{3} - 15 A b^{2} d e^{2} - 3 B a^{2} e^{3} + 15 B a b d e^{2}\right )}{6 a^{3} d^{3} e^{4} - 18 a^{2} b d^{4} e^{3} + 18 a b^{2} d^{5} e^{2} - 6 b^{3} d^{6} e + x^{3} \left (6 a^{3} e^{7} - 18 a^{2} b d e^{6} + 18 a b^{2} d^{2} e^{5} - 6 b^{3} d^{3} e^{4}\right ) + x^{2} \left (18 a^{3} d e^{6} - 54 a^{2} b d^{2} e^{5} + 54 a b^{2} d^{3} e^{4} - 18 b^{3} d^{4} e^{3}\right ) + x \left (18 a^{3} d^{2} e^{5} - 54 a^{2} b d^{3} e^{4} + 54 a b^{2} d^{4} e^{3} - 18 b^{3} d^{5} e^{2}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x+A)/(b*x+a)/(e*x+d)**4,x)

[Out]

b**2*(-A*b + B*a)*log(x + (-A*a*b**3*e - A*b**4*d + B*a**2*b**2*e + B*a*b**3*d - a**5*b**2*e**5*(-A*b + B*a)/(
a*e - b*d)**4 + 5*a**4*b**3*d*e**4*(-A*b + B*a)/(a*e - b*d)**4 - 10*a**3*b**4*d**2*e**3*(-A*b + B*a)/(a*e - b*
d)**4 + 10*a**2*b**5*d**3*e**2*(-A*b + B*a)/(a*e - b*d)**4 - 5*a*b**6*d**4*e*(-A*b + B*a)/(a*e - b*d)**4 + b**
7*d**5*(-A*b + B*a)/(a*e - b*d)**4)/(-2*A*b**4*e + 2*B*a*b**3*e))/(a*e - b*d)**4 - b**2*(-A*b + B*a)*log(x + (
-A*a*b**3*e - A*b**4*d + B*a**2*b**2*e + B*a*b**3*d + a**5*b**2*e**5*(-A*b + B*a)/(a*e - b*d)**4 - 5*a**4*b**3
*d*e**4*(-A*b + B*a)/(a*e - b*d)**4 + 10*a**3*b**4*d**2*e**3*(-A*b + B*a)/(a*e - b*d)**4 - 10*a**2*b**5*d**3*e
**2*(-A*b + B*a)/(a*e - b*d)**4 + 5*a*b**6*d**4*e*(-A*b + B*a)/(a*e - b*d)**4 - b**7*d**5*(-A*b + B*a)/(a*e -
b*d)**4)/(-2*A*b**4*e + 2*B*a*b**3*e))/(a*e - b*d)**4 + (-2*A*a**2*e**3 + 7*A*a*b*d*e**2 - 11*A*b**2*d**2*e -
B*a**2*d*e**2 + 5*B*a*b*d**2*e + 2*B*b**2*d**3 + x**2*(-6*A*b**2*e**3 + 6*B*a*b*e**3) + x*(3*A*a*b*e**3 - 15*A
*b**2*d*e**2 - 3*B*a**2*e**3 + 15*B*a*b*d*e**2))/(6*a**3*d**3*e**4 - 18*a**2*b*d**4*e**3 + 18*a*b**2*d**5*e**2
- 6*b**3*d**6*e + x**3*(6*a**3*e**7 - 18*a**2*b*d*e**6 + 18*a*b**2*d**2*e**5 - 6*b**3*d**3*e**4) + x**2*(18*a
**3*d*e**6 - 54*a**2*b*d**2*e**5 + 54*a*b**2*d**3*e**4 - 18*b**3*d**4*e**3) + x*(18*a**3*d**2*e**5 - 54*a**2*b
*d**3*e**4 + 54*a*b**2*d**4*e**3 - 18*b**3*d**5*e**2))

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